The simplified problem statement is as follows.
Given a sequence of 0 and 1s. Check if contains a continuous sequence of 0/1 of length 7.
For example see some input output combinations
Your program should accept a sequence of 0, 1s as input and print YES of there is a sequence of 7 0/1s in it or NO if does not contain such a sequence.
The algorithm is as follows.
We maintain a state variable to see if we are getting a sequence 0s or sequence of 1s. We also use a continuity counter to track the maximum number of similar symbols. If this counter reaches 7 anytime we break and declare the result as YES.
If we finish processing the input without the counter reaching 7 anytime, we output the result as NO.
Here is the C++ implementation of the above algorithm.